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The volume of the lunch box is 300 cubic m and the area of the upper face is 20sq m. The total surface area of the lunch box is 490sq m find the approximate value of length, breadth, and height of the lunch box?
13m,14m,12m
1.5m ,3.5m ,7m
15m ,13.5m ,2.5m
1.5m ,13.5m ,15m
let l,b, and h be the length, breadth, and height of the lunch box given l×b×h=300 m^3.....1 2(lb + bh + hl)=490 m^2....2 lb=20m^2.....3 from 3 and 1 we get h=15m on putting value of h in 2 we get 20+h(b+l)=245 =h(b+l)=225 =(b+l)=15.....4 now (b-l)^2=(b+l)^2 -4bl =(15)^2-4×20 =225-80 =145 sq m b-l~12....5 adding 4 and 5 we get 2b=27 b=13.5 m from 4 l=1.5 m
By: bhavesh kumar singh ProfileResourcesReport error
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