One bag contains 3 red balls and 4 green balls Another bag contains 4 red balls and 5 green balls If...........

Quantitative Aptitude (CDS) Probability

One bag contains 3 red balls and 4 green balls. Another bag contains 4 red balls and 5 green balls. If one ball is drawn from each bag, determine the probability that one ball is red and another is green.

1/63

31/63

1/31

16/63

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Explanation:

The probability that first ball is red and second is green
= 3/7 × 5/9
= 15/63
The probability that first ball is green and second is red
= 4/7 × 4/9
= 16/63
These are mutually exclusive events, hence the required probability
= 15/63 + 16/63
= 31/63