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A cistern has two pipes who can fill it in 12 and 15 minutes respectively. there is also a leak pipe C at the bottom of the cistern. If all the three pipes are opened simultaneously the cistern got completely filled in 20 minutes. In how much time the leak alone can empty the tank completely?
6minutes
8minutes
10minutes
12minutes
Let the third pipe be x.Then, 20/12 +20/15 - 20/x = 1 3-20/x = 1 20/x = 2 x = 10minutes
By: bhavesh kumar singh ProfileResourcesReport error
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