If one root of the equation a 2 5a 3 x 2 3a 1 x 2 0 is twice the other root then what...........

Quantitative Aptitude (CDS) Time and work

If one root of the equation (a^2 -5a +3)x^2 + (3a - 1)x + 2 = 0 is twice the other root then, what is the value of a?

1/3

2/3

3/4

5/8

a+b= -(3a-1)/a^2-5a+3 and a×b=2/a^2-5a+3

Now a×2a=2/a^2-5a+3 or a^2=1/a^2-5a+3 …. equation 1.

a+2a=-(3a-1)/a^2-5a+3 or a=-(3a-1)/3(a^2-5a+3) and a^2={(3a-1)/3(a^2-5a+3)}^2…... equation 2.

Now equation 1 and equation 2 are equal.

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