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A bag contains 8 green and 7 blue balls. Three balls are drawn at random. What is the probability that 1 is green and 2 is blue?
1-29/455
39/455
29/455
1-39/455
Let S be the sample space and E be the event of drawing 3 balls out of which 2 are blue and 1 is green. Then, n (S) = Number of ways of drawing 3 balls out of 15 = 15C3 =455 and n (E) = Number of ways of drawing 2 balls out of 7and 1 ball out of 8. = 7C2 + 8C1 =21+8 =29 P (E) =n (E)/n (S) =29/455
By: bhavesh kumar singh ProfileResourcesReport error
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