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How many numbers between 700 and 2000 that can be formed with the digits 7, 8,9,1 and 5 assuming repetition of digits not allowed.
45
40
60
50
Any number between 700 and 2000 must be of 3 or 4 digits. When the number is 3 digits. Hundreds place can be filled up by any one of the three digits 7, 8, and 9 in 3 ways. Remaining two places can be filled up by the remaining four digits in 4P2 ways. the number formed in this case = 3 × 4P2 = 3 × 4! /2! = 36 When the number is of 4 digits Thousands place can be filled up by one digits 1 three places can be filled up by the remaining four digits in 4P3 ways. Number of numbers formed in this case = 1 × 4P3 = 1 × 4! /3! = 4 Required number = 36 + 4 = 40
By: bhavesh kumar singh ProfileResourcesReport error
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