Hari had three notebooks X Y Z Of these X had 120 pages Y had 10 more pages than X and Z had 10 fewe...........

Quantitative Aptitude (CDS) Percentage

Hari had three notebooks X, Y, Z. Of these, X had 120 pages. Y had 10% more pages than X and Z had 10% fewer pages than X. If he tore roughly 5%, 10%, and 15% of pages in X, Y, and Z respectively, then what percent of pages did he tear out?

34%

10%

19%

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Explanation:

Given, Total No. of pages in book X = 120
Total No. of pages in book Y = 10% more of Total No. of pages in book X
= 10% of 120 + 120
= 12 + 120
= 132

Total No. of pages in book Z = 10% less of Total No. of pages in book X
= 120 - 10% of 120
= 120 - 12
= 108

No. of pages torn from book X = 5% of Total No. of pages in book X
= (5/100) * 120
= 6
No. of pages torn from book Y = 10% of 132 = 13.2
No. of pages torn from book Z = 15% of 108 = 16.2
Total No. of pages torn out from books X, Y, and Z = 6 + 13.2 + 16.2 = 35.4

Now, Total No. of pages in books X, Y, and Z earlier = 120 + 132 + 108 = 360

Required Percentage = (Total No. of pages torn out/Total No. of pages in books X, Y, and Z earlier) * 100
= (35.4/360) * 100
= 9.83%
≅ 10%