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Two trains, each 120 m long, moving in opposite directions cross each other in 10 seconds. If one is moving twice as fast the other, then the speed of the faster train is:
57.6kmph
56.7kmph
54.2kmph
58.1kmph
Let the speed of the slower train be x m/sec. Then. speed of the faster train = 2x m/sec.
Relative speed= (x + 2x) m/sec = 3x m/sec
(120+120)/10 = 3x = 30x = 240
x = 240/30 = 8. x=8m/sec
So speed of the faster train = 16m/sec = (16x18/5)km/hour = 57.6km/hour
By: bhavesh kumar singh ProfileResourcesReport error
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