From an external point P tangents PA and PB are drawn to the circle as shown in the above figure CD ...........

Quantitative Aptitude (CDS) Mensuration 2D

From an external point P tangents PA and PB are drawn to the circle as shown in the above figure. CD is the tangent to the circle at E. If AP = 16 cm, then the perimeter of the triangle PCD is equal to

24 cm

28 cm

30 cm

32 cm

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Explanation:

Remember:
The lengths of tangents drawn from an external point to a circle are equal.
∴ AC = CE ....(1)
BD = DE ....(2)
PB = PA
=16 cm
∴ PA + PB = 32 cm
⇒(PC + AC) + (PD + BD) = 32cm
⇒ PC + (CE + DE) + PD = 32cm
[Using (1) and (2)]
⇒PC + CD + PD = 32 cm
Therefore, perimeter of ΔPCD = 32 cm