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The area of a trapezium is 336 cm2. If its parallel sides are in the ratio 5 : 7 and the perpendicular distance between them is 14 cm, then the smaller of the parallel sides is
20 cm
22 cm
24 cm
26 cm
Let the parallel sides of the trapezium be 5k and 7k Area of the trapezium =1/2 × Sum of the parallel sides × Perpendiculardistance between the parallel sides ∴1/2×(5k+7k)×14=336 ⇒84k=365 ⇒k=4 Therefore, smaller of the parallel sides =5×4=20cm
By: Munesh Kumari ProfileResourcesReport error
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