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A triangle ABC is inscribed in a circle. If sum of the squares of sides of the triangle is equal to twice the square of the diameter, then sin2 A + sin2 B + sin2 C is equal to
2
3
4
None of the above
Remember: If a triangle is inscribed in a circle such that the sum of the squares of sides of the triangle is equal to twice the square of diameter, then the triangle is a right-angled triangle whose hypotenuse is the same as the diameter of the circle. In right ΔABC, ∴sin2A+sin2B+sin2C =sin290°+sin2B+sin2(90°−B) =1+sin2B+cos2B =1 +1=2 (sin2θ+cos2θ=1)
By: Munesh Kumari ProfileResourcesReport error
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