The sides of a triangular field are 41 m 40 m and 9 m The number of rose beds that can be prepared i...........

Quantitative Aptitude (CDS) Mensuration 2D

The sides of a triangular field are 41 m, 40 m and 9 m. The number of rose beds that can be prepared in the field if each rose bed, on an average, needs 900 square cm space, is

2000

1800

900

800

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Explanation:

40²+9²=1681=41²
So, the sides of the triangular fieldform a right-angled triangle whose hypotenuse is 41 m and the lengths of the other two sides are 40 m and 9 m.
Therefore, the number of rose beds that can be prepared in the field

=Area of the triangular field/Average area needed by each rose bed
=(1/2) x 4000 x 900/900=2000