Find the value of 1 3 log10125 minus 2log104 log1032 ........

Quantitative Aptitude (CDS) Logarithm

Find the value of (1/3)log₁₀125−2log₁₀4+log₁₀32

(1/3)log₁₀125−2log₁₀4+log₁₀32
=log₁₀(125^1/3)−log₁₀(4²)+log₁₀32
=log₁₀5−log₁₀16+log₁₀32
=log₁₀(5×32/16)
=log₁₀(10)
=1

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