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Multiple Choice Questions

logx 9 32 minus 1 8 find the value of x ........

Quantitative Aptitude (CDS) Logarithm

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log_x(9/32)=−1/8, find the value of x

$\left ( \frac{9}{32} \right )^{8}$

$\left ( \frac{9}{32} \right )^{2}$

$\left ( \frac{32}{9} \right )^{8}$

$\left ( \frac{32}{9} \right )^{2}$

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Explanation:

$logx \left ( \frac{9}{32} \right )=-\frac{1}{8}$
⇒x^−1/8=9/32
⇒1/x^1/8=9/32
⇒x^1/8=32/9
⇒x=(32/9)⁸

By: Munesh Kumari

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