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If cos2x+cosx=1, then what is value of sin12x+3sin10x+3sin8x+sin6x?
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cos2x+cosx=1 => cosx=1-cos2x=sin2x sin12x+3sin10x+3sin8x+sin6x = sin6x(sin6x+3sin4x+3sin2x+1) =sin6x(sin2x+1)3 = [sin2x(sin2x+1)]3 = [sin4x+sin2x]3 = (cos2x+cosx)3 = 13 =1 (sin4x= cos2x , sin2x=cosx)
By: Munesh Kumari ProfileResourcesReport error
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