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Let XYZ be an equilateral triangle in which XY =7 cm. If A deontes the area of the triangle , then what is the value of log10A4? Given that log101050 =3.0212 and log1035=1.5441)
5.3070
5.3700
5.5635
5.6535
log101050 = log103x10x35 = log103 + 1 +log1035 => 3.0212 = log103 + 1 + 1.5441 => log103 = 0.4771 Next, log1035 = log( 7x10)/2 = log107+log1010 - log102 => 1.5441 = log107 + 1 - 0.3010 => log107=0.8451 Now A = /4(7)2 => log10A4 = 4 log10A = 4 log (/4(7)2) = 4[ 1/2log103 + 2log107-2log102] = 5.3070
By: Munesh Kumari ProfileResourcesReport error
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