Walls excluding roofs and floors of 5 identical rooms having length breadth and height 6 m 4 m and 2...........

Quantitative Aptitude (CDS) Mensuration 3D

Walls (excluding roofs and floors) of 5 identical rooms having length, breadth and height 6 m, 4 m and 2.5 m respectively are to be painted. Out of five

rooms, two rooms have one square window each having a side of 2.5 m. Paints are available only in cans of 1 litre; and 1 litre of paint can be used for painting 20 square metres. The number of cans required for painting is

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Explanation:

Length (L) = 6m , Breadth (B) = 4m , Height (H) = 2.5m
CSA of room = 2(L+B)H = 2(6+4) x 2.5 = 50 sq.metre
CSA of 5 rooms = 50 x 5 = 250 sq.metre
Side of window = 2.5m
Area of window = 2.5 x 2.5 = 6.25 sq. metre
Area of 2 window = 2 x 6.25 = 12.5 sq. metre
Net area to be painted = 250 - 12.5 = 237.5 sq. metre
20 m²require = 11
1m²require = (1 / 20)L , 237.5 m² will require = (1/20)x 237.5 L = 11.875
Thus, 12 cans are required.