A thief steals a car parked in a house and goes away with a speed of 40 kmph The theft was discovere...........

Quantitative Aptitude (CDS) Time & distance

A thief steals a car parked in a house and goes away with a speed of 40 kmph. The theft was discovered after half an hour and immediately the owner sets off in another car with a speed of 60 kmph. When will the owner meet the thief?

55 km from the owner’s house and one hour after the theft.

60 km from the owner’s house and 1.5 hours after the theft

60 km from the owner’s house and 1.5 hours after the discovery of the theft

55 km from the owner’s house and 1.5 hours after the theft

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Explanation:

Let the owner meets thief x hours after discovering theft.
Distance travelled by thief till then = 40 (x + 1/2)
Distance travelled by owner till then = 60(x)
According to question,
60(x) = 40 (x + 1/2)
60x = 40x + 20
20 x = 20
X = 1 hour
Distance travelled = 60 x 1 = 60km
They meet 60km from owner’s house & 1.5 hour after theft.