send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
The sum of ages of a father, a mother, a son Sonu and daughters Savita and Sonia is 96 years. Sonu is the youngest member of the family. The year Sonu was born, the sum of the ages of all the members of the family was 66 years. If the father’s age now is 6 times that of Sonu’s present age, then 12 years hence, the father’s age will be
44 years
45 years
46 years
48 years
We shall use F for father, M for mother, A for Sonu, B for Savita & C for Sonia (for present ages) F + M + A + B + C = 96 When Sonu was born: (F - A) + (M - A) + (A - A) + (B - A) + (C - A) = 66 F + M + A + B + C - 5A = 66 96 - 5A = 66 5A = 96 - 66 = 30 A = 30/5 = 6 Also, F = 6A = 6 x 6 = 36 years After 12 years Father’s age = F + 12 = 36 + 12 = 48 years
By: Munesh Kumari ProfileResourcesReport error
Access to prime resources
New Courses