Considering two opposite vertices of a square of side lsquo a rsquo as centres two circular arcs are...........

Quantitative Aptitude (CDS) Mensuration 2D

Considering two opposite vertices of a square of side ‘a’ as centres, two circular arcs are drawn within the square joining the other two vertices, thus forming two sectors. What is the common area in these two sectors?

$a^{2}(\pi+\frac{1}{2})$

$a^{2}(\pi-\frac{1}{2})$

$a^{2}(\frac{\pi}{2}-1)$

$a^{2}(\frac{\pi}{2}+1)$

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Explanation:

Area of leaf BEDFB = Area of two quarter circle – area of square
= 2πr²/4 – a²
= πa²/2 – a²= a²(π/2 - 1)

By: Munesh Kumari

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Considering two opposite vertices of a square of side lsquo a rsquo as centres two circular arcs are...........

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Explanation:

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