The corners of a square of side lsquo a rsquo are cut away so as to form a regular octagon What is t...........

Quantitative Aptitude (CDS) Mensuration 2D

The corners of a square of side ‘a’ are cut away so as to form a regular octagon. What is the side of the octagon?

$a(\sqrt{2}-1)$

$a(\sqrt{3}-1)$

$\frac{a}{\sqrt{2}+2}$

a / 3

Let side of hexagon be x

AE² + AL² = LE²

Since we are forming a regular octagon so AE = AL = FB = BG and so on

So AE = SB = x/√2

AE + EF + FB = side of square = a (Given)

So x/√2 + x + x/√2 = a

X = a/(√2+1) = a(√2 - 1)

Submit Error