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Direction: Consider the following for the next two (02) items: The sum of length, breadth and height of a cuboid is 22 cm and the length of its diagonal is 14 cm.
If S is sum of the cubes of the dimensions of the cuboid and V is its volume, then what is (S-3V) equal to?
572 cm3
728 cm3
1144 cm3
None of the above
Let lengths, breadth and height of cuboid be l, b and h respectively According to question l+b+h = 22cm……(i) and √(l2+b2+h2) = 14cm …..(ii) S = l3+b3+h3 and V = lbh S-3V = l3+b3+h3 - 3 lbh = (l+b+h)( l2+b2+h2-[lb+bh+lh])…(iii) As we know Squaring eq (i) gives l2+b2+h2 + 2(lb+bh+lh) = 484 Substituting l2+b2+h2 from eq (i) 2(lb+bh+lh) = 484-196 = 288 cm2 lb+bh+lh = 144 cm2 Putting this in eq (iii) we get 22(196-144) = 22*52 = 1144cm2
By: Munesh Kumari ProfileResourcesReport error
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