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Direction: Consider the following for the next three (03) items: ABCD is a quadrilateral with AB = 9 cm, BC = 40 cm, CD = 28 cm, DA = 15 cm and angle ABC is a right – angel.
What is the area of triangle ADC?
126 CM2
124 CM2
122 CM2
120 CM2
Area of triangle ADC = (s(s − a)(s − b)(s − c))1/2 Where s is the semi perimeter of triangle = (AD + DC + CA) / 2 = 15+28+41 / 2 = 42 cm Area = (42(42−15)(42−28)(42−41))1/2 = (42∗27∗14∗1)1/2 = 126 cm2
By: Munesh Kumari ProfileResourcesReport error
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