In the figure given below SPT is atangent to the circle at P and O is the centre of the circle If QP...........

Quantitative Aptitude (CDS) Coordinate Geometry

In the figure given below, SPT is atangent to the circle at P and O is the centre of the circle. If $\angle$ QPT = $\alpha$ , then what is $\angle$ POQ equal to?

$\alpha$

2 $\alpha$

90^o- $\alpha$

180^o- 2 $\alpha$

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Explanation:

∠ QPT = α, ∠ OPT = 90o ∠ OPQ = OQP = 90 - α (isosceles triangle)

∠ POQ = 180 – (90- α + 90 - α) (Sum of all the angles of triangle OPQ is 180^o) = 2 α

Hence, option (2) is correct

By: Munesh Kumari

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In the figure given below SPT is atangent to the circle at P and O is the centre of the circle If QP...........

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Explanation:

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