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In the figure given below, XA and XB are two tangents to a circle, If AXB = 50o and AC is parallel to XB, then what is ACB equal to?
70o
65o
60o
55o
Let O be the center of the circle.
Now, angle OAX = angle OBX = 90o
In polygon AOBX, Angles (AOB + OBX + BXA + XAO) = 360o
Thus, angle AOB = 360 – (90 + 90 + 50) = 130o
angle ACB = ½ angle AOB = ½ of 130 = 65o
By: Munesh Kumari ProfileResourcesReport error
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