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Each side of a square subtends an angle of 60° at the tip of a tower of height h metres standing at the centre of the square. If I is the length of each side of the square, then what is h2 equal to?
2l2
l2 / 2
3l2/2
2l2/3
Diagonal of the square => AC2 = 2l2 (where l is the side of the square) AC = √2l
AE (Base of the triangle formed by the vertex of the square with the tip of the tower) = ½AC = √2l/2
Also, angle DAE = 60o
In triangle ADE, tan 60 = h/(√2l/2)
h= √2/2 * √3 * l
h2 = (3/2) l2
By: Munesh Kumari ProfileResourcesReport error
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