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The age of a woman is a two-digit integer. On reversing this integer, the new integer is the age of her husband who is elder to her. The difference between their ages is one-eleventh of their sum. What is the difference between their ages?
8 years
9 years
10 years
11 years
Let the age of women = 10x + y
The age of husband = 10y +x
According to question (10y+x) – (10x +y) = 1/11 (10x+y+10y+x)
9y-9x = 1/11 (11x+11y)
9y - 9x = x + y ……(a)
8y = 10x
x = 8y/10
x= 4/5 y
Difference of their ages 9y - 9x = 4y/5 +y
9y - 9x = 9y/5
So, the difference of their ages is multiple of 9.
By: Munesh Kumari ProfileResourcesReport error
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