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A circle of radius 10 cm has an equilateral triangle inscribed in it. The length of the perpendicular drawn from the centre to any side of the triangle is
2.5 √3 cm
5 √3 cm
10 √3 cm
None of these
Circumradius =2/3×Height Height =10×3/2= 15 cm So, length of perpendicular drawn from center = 15– 10 = 5 cm.
By: Munesh Kumari ProfileResourcesReport error
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