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Let ABC be a triangle in which AB =AC. Let L be the locus of points X inside or on the triangle such that BX =CX. Which of the following statements are
correct?
1. L Is a straight line passing through A and in-centre of triangle ABC is on L.
2. L is a straight line passing through A and orthocentre of triangle ABC is a point on L.
3. L is a straight line passing through A and centroid of triangle ABC is a point on L.
Select the correct answer using the code given below:
1 and 2 only
2 and 3 only
1 and 3 only
1, 2 and 3
Locus of the point X is L. Here L is line segment AD. Now, Δ AXB ≅ Δ AXC (By SSS) ∴ ∠BAX =∠CAX (Corr. Angles) ⇒ AX and hence AD is the bisector of ∠BAC. Hence in centre of the ΔABC lies on AD i.e., L (statement 1 is correct) Since AB = AC, Find AD is the bisector of ΔABC Now ΔXBD ≅ ΔXCD (By SSS) ∠XDB = ∠XDC = 90° Hence AD is the perpendicular bisector of BC. Therefore, orthocentre of the ΔABC lies on AD i.e, L. (Statement 2 is correct) Since D is the mid-point of BC, therefore AD is the medium. Hence centroid of the ΔABC lies on AD i.e., L. (Statement 3 is correct)
By: Munesh Kumari ProfileResourcesReport error
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