An aeroplane flying at a height of 3000 m passes vertically above another aeroplane at an instant wh...........

Quantitative Aptitude (CDS) Coordinate Geometry

An aeroplane flying at a height of 3000 m passes vertically above another aeroplane at an instant when the angles of elevation of the two planes from

some point on the ground are 60° and 45° respectively. Then the vertical distance between the two planes is

1000 (√3 − 1) m

1000 √3m

1000(3 − √3)m

3000 √3m

CP1= 3000 m
OC =CP1/tan60°=3000/√3 m
CP2 = OC =3000/√3 m
P1 P2 = CP1 − CP2 = (3000 −3000/√3)
= (3000 – 100 √3) m = 1000 (3- √3) m

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