A person travels 7 km cast wards and then turns right and travels 3 km and further turns right and t...........

Quantitative Aptitude (CDS) Height and Distance

A person travels 7 km cast wards and then turns right and travels 3 km and further turns right and travels 13 km. What is the shortest distance of the

present position of the person from his starting point?

6 km

$\small 3\sqrt{5}$ km

7 km

$\small 4\sqrt{5}$ km

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Explanation:

Let the position of person = A
We have to find out the distance between A and E.

AB = 7 km then CD = 7 km
BC = 3 m then AD = 3 km
DE = CE – CD = 13 – 7 = 6 km
Draw AD⊥ CE
In right angled triangle AED, we get
(AE)²= AD^₂= DE²
= (3)²+(6)²
AE = √9 + 36
= √45 = √5×9
AE = 3√5km