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If one the roots of the equation px2 − qx + r = 0 is three times the other, then which one of the following relation is correct?
3q2 − 16pr
q2 − 24pr
p = q + r
p+ q + r = 1
Given equation px2 − qx + r = 0 Let one root of the equation be a So, other root = 3 a Sum of roots = a + 3a = − (q/p) a = − ( q/4p) …. (i) Product of roots = a. 3a = (r/p)⇒ 3a2 = (r/p) ⇒3(−q4p)/2= (r/p) = 3q2=16pr
By: Munesh Kumari ProfileResourcesReport error
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