A B and C can do a piece of work individually in 8 12 and 15 days respectively A and B start working...........

Quantitative Aptitude (CDS) Time and work

A, B and C can do a piece of work individually in 8, 12 and 15 days, respectively. A and B start working together but A quits after working for 2 days. After this, C joins and works till completion of the work. In how many days, will the work be completed?

$3\frac{8}{9} days$

$5\frac{8}{9}days$

$5\frac{2}{3}days$

$6\frac{1}{18}days$

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Explanation:

A = 8, B = 12, C = 15

Here, 120 is total work
(A + B) starts together in 1 day work = 15 + 10 = 25
2 days work of (A + B) = 25× 2 = 50
Remaining work = 120 – 50 = 70
Now, (B + C) work together in 1 day = 10 + 8 = 18days
(B + C) Complete in days =70/18=35/9
$3\frac{8}{9}\: days$
A worked for 2 days.
So A, B, C all 3 completed work in 2+ $3\frac{8}{9}\: days$
$5\frac{8}{9} days$