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A, B and C can do a piece of work individually in 8, 10 and 15 days, respectively. A and B start working but A quits after working for 2 days. After
this, C joins B till the completion of work. In how many days will the work be completed?
53/9 days
34/7 days
85/13 days
53/10 days
A work in one day =1/8 B work in one day =1/10 C work in one day =1/15 A+B work in one day =1/8+1/10=9/40 A+B work in two day =2×9/40=9/20 Remaining work 1 -9/20=11/20 B + C work in one day =1/10+1/15=1/6 So, (B+ C) a work together in 6 days.11/20 Work together = 6×11/20 =11×3/10=33/10 days
total days=2+33/10=53/10days
By: Munesh Kumari ProfileResourcesReport error
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