In a race of 100 m A beats B by 4m and A beats C by 2 m By how many metres approximately would C bea...........

Quantitative Aptitude (CDS) Time & distance

In a race of 100 m, A beats B by 4m and A beats C by 2 m. By how many metres (approximately) would C beat B in another 100 m race assuming C and B run with their respective speeds as in the earlier race

2.04

2.08

3.2

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Explanation:

In a race of 100 m
When A covers total 100 m.
B will cover = 100 – 4 = 96 m
C will cover = 100 – 2 = 98 m
When C covers 98 m, B covers = 96 m
When C covers 100 m, B will cover =96/98× 100=4800/49m
So C will beat B by = 100 –4800/49

⇒4900−4800/49=100/49
= 2.04 m