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A cyclist moves non-stop from A to B, a distance of 14 km, at a certain average speed. If his average speed reduces by 1 km per hour, he takes 20 minutes more to cover the same distance. The original average speed of the cyclist is
5 km/hour
6 km/hour
7 km/hour
None of the above
Let Average speed = x km/hr Time taken = t hr Distance = 14 km ⇒ x = 14 / t . . ................... (1) According to question, Now Average speed = (x – 1) km/hr Time taken = (t +20 / 60 )hr =(t +1 / 3)hr Distance = 14 km x - 1 = 14 / ( t +1/3 ) => 14/t - 1 = 14 / (t + 1/3) x = 14/t
( 14 - t) ( 3t + 1) = 42t
Solving we get ( t = 2) and ( t = - 7/3)
t = 2 is the only possible solution, putting value of t in equation 1
x = (14 / 2) = 7 km hr.
By: Munesh Kumari ProfileResourcesReport error
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