send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
A man walking at 5 km/hour noticed that a 225 m long train coming in the opposite direction crossed him in 9 seconds. The speed of the train is
75 km/hour
80 km/hour
85 km/hour
90 km/hour
Let the speed of train = x km/hr Distance of train = 225 m = 225 / 1000 km Time taken = 9 sec = 9/3600 hr Speed of man = 5 km/hr Relative speed = Speed of train + speed of man = (x + 5) km/hr But relative speed = (225/1000) X (3600/9) = 90 km/hr x + 5 = 90 x = 85 km/hr
By: Munesh Kumari ProfileResourcesReport error
Access to prime resources
New Courses