A tank can be filled by pipe X in 2 hours and pipe Y in 6 hours At 10 a m pipe X was opened At what ...........

Quantitative Aptitude (CDS) Time and work

A tank can be filled by pipe X in 2 hours and pipe Y in 6 hours. At 10 a.m. pipe X was opened. At what time will the tank be filled if pipe Y is opened at 11 a.m.?

12:45 hours

5:00 p.m.

11:45 a.m.

11:50 a.m.

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Explanation:

Total work = LCM of 2 and 3
X will perform =6 / 2 = 3 unit/hr
Y will perform =6 / 6=1 unit/hr
X perform between 10:00 AM to 11:00 AM = 6 – 3 = 3 unit.
Now, x and y together will perform = 3 + 1 = 4 unit.
Time taken for remaining work = 34×60 min. = 45min.
Hence tank be filled at 11:45 AM
Hence option (3)