Explanation:

Let x and y be 2n+1 and 2n+3 respectively.
Then,
x²+y²=(2n+1)²+(2n+3)²
=8n²+16n+10
=8n²+16n+8+2
=4[2n²+4n+2]+2
i.e. x²+y² is an odd number but not necessarily a multiple of 4
Hence only statement 1 is correct.
Hence option (1)