Two men A and B run a 4 km race on a course 0 25 km round If their speeds are in the ratio 5 4 how o...........

Quantitative Aptitude (CDS) Time & distance

Two men, A and B run a 4 km race on a course 0.25 km round. If their speeds are in the ratio 5 : 4, how often does the winner pass the other ?

Once

Twice

Thrice

Four times

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Explanation:

Total number of rounds = Total distance / Distance per round =40 / 25=16
Speed of A : Speed of B =5:4
As we know that time ?? 1/ speed
So, time taken by A : time taken by B =4:5
LCM of (4, 5) = 20
Number of Rounds completed by A = 204=5
Number of Rounds Completed by B = 205=4
When A will complete 5 rounds then B will complete 4 round and they meet at a point.
i.e. If A will complete 5×3 i.e. 15 rounds
Then he will meet to B.
Hence A will trice pass the B.