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An isosceles triangle is drawn outside on one of the sides of a square as base in such a way that the perimeter of the complete figure is 7/6 times the perimeter of the original square. What is the ratio of area of the triangle to the area of the original square?
1 : 1
2 : 3
1 : 2
1 : 3
Let the side of each of the square be a and the other two sides of the triangle be x Given, Perimeter of the complete figure = 7/6(perimeter of the original square) =>3a + 2x = 7/6(4a) =>3a + 2x = 7/3(2a) =>3(3a + 2x) = 14a =>9a + 6x = 14a =>6x = 5a ………(i) Using Pythagoras theorem In upper triangle: Again, Ratio of the area of triangle to the original square = Hence required ratio be 1 : 3
By: Munesh Kumari ProfileResourcesReport error
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