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ABCDEF is a regular polygon. Two poles at C and D are standing vertically and subtend angles of elevation 30o and 60o at A respectively. What is the ratio of the height of the pole at C to that of the pole at D?
1:1
∠ABC = 1200 [Angle of regular hexagon] ∠BAC = ∠BCA =(1800−1200)/2= 300 ∠DCA = 1200 – 300 = 900 Thus, ADCA is a right triangle. Let side DC = a AC/a=cot30o=AC=√3a AD/a=cosec 30o=>AD=2a Now taking triangle ASD: Let S is the vertex of pole DS/AC=tan30o=>DS=2√3 In triangle TCA: TC/AC=tan30o => TC =√3a /√3= a Thus, ratio ∅ CT/DS=a/2√3a=1/2√3 Hence CT : DS = 1 : 2√3
By: Munesh Kumari ProfileResourcesReport error
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