Consider the following distribution Class Frequency 0 20 17 20 40 28 40 60 32 60 80 F 80 100 19...........

Quantitative Aptitude (CDS) Average

Consider the following distribution :

Class	Frequency
0-20	17
20-40	28
40-60	32
60-80	F
80-100	19

If the mean of the above distribution is 50, what is the value of F?

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Explanation:

Class	Mid Value(Xi)	Frequency(fi)	xi*fi
0-20	10	17	170
20-40	30	28	840
40-60	50	32	1600
60-80	70	F	70F
80-100	90	19	1710

$Mean=\frac{\sum xi*fi}{\sum fi}=\frac{170+840+1600+70F+1710}{17+28+32+F+19}$
$=>\frac{4320+70F}{96+F}=50$
=>4320 + 70F = 50(96 + F)
=>70F − 50F = 4800 − 4320
=>20F = 480
=>F = 24

By: Munesh Kumari

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Consider the following distribution Class Frequency 0 20 17 20 40 28 40 60 32 60 80 F 80 100 19...........

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Explanation:

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