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Sunil wants to spend Rs200 on two types of sweets, costing Rs7 and Rs10 respectively. What is the maximum number of sweets he can get so that no money is left over?
25
26
27
28
Possibility 1: Number of sweets, costing Rs. 7 be 10 Then money speed = Rs. (10 × 7) =Rs. 70 Money left = 200 − 70= Rs. 130 Number of sweets costing Rs. 10=130/10= 13 Number of sweets = 10 + 13 = 23 In this possibility no money is left over. Possibility 2: Number of sweets, costing Rs. 7 be 20 Then money spend = Rs. (7 × 20) =Rs. 140 Money left = 200 − 140 = Rs. 60 Number of sweets costing Rs. 10=60/10= 6 Number of sweets = 20 + 6 = 26 Here, also no money is left over. Hence, maximum number of sweets Sunil can get 26. So that no money is left over.
By: Munesh Kumari ProfileResourcesReport error
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