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A parallel-plate capacitor, with air in between the plates, has capacitance C. Now the space between the two plates of the capacitor is filled with a dielectric of dielectric constant 7. Then the value of the capacitance will become
C
c/7
7C
14C
As the capacitance is charged by the factor equal to the value of dielectric constant, Hence, C’ = kC = 7C.
By: Ketan Garg ProfileResourcesReport error
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