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Suppose voltage V is applied across a resistance R. The power dissipated in the resistance is P. Now the same voltage V is applied across a parallel combination of three equal resistors each of resistance R. Then the power dissipated in the second case will be
P
3P
p/3
2p/ 3
P= I^2.R where, I= Current, P= Electric Power, R=Resistance. Here all the resistance is put in parallel combination and in parallel combination the value of Resistance decreases and dissipation of power increase, hence 3 times more power will be dissipated(3P).
By: Ketan Garg ProfileResourcesReport error
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