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Two persons are holding a rope of negligible mass horizontally. A 20 kg mass is attached to the rope at the midpoint; as a result the rope deviates from the horizontal direction. The tension required to completely straighten the rope is
200 N
20 N
10 N
infinitely large
let T be the tension in string. For equilibrium 2TCosx= mg string will be straight if x = 90 degrees. and Cos 90 = 0; T= mg/2 Cos 90. So, T=infinity.
By: Ketan Garg ProfileResourcesReport error
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