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You must be well aware that Distance & Direction is the part of the Reasoning Section of any banking exam and truly saying, this is one of the easiest topics you can ever encounter. So to make sure that you don't miss out any question from this topic in Exam, we are going to discuss the basics of distance & direction in this article.
As the name of the topic clearly explains that we deal with finding distance or direction in the questions of this topic. But for dealing with the questions from this topic, we must have a very clear idea about two things.
1. Basic Directions: We have 8 basic directions which should be crystal clear to us for attempting distance and direction questions.
One key point that should be kept in mind is that If not mentioned we always assume that the person is facing north.
2. Pythagoras theorem: According to this theorem,” The square of Hypotenuse is always equal to the sum of the squares of the other two sides of the right angle triangle”.
Suppose we have a triangle having base p, height q and hypotenuse r. Then according to this theorem:
p2+q2=r2
Now you have the basics required to atttempt Distance & Direction questions. So let us try to look at few questions on the same so that you will get to know the proper approach to solve these questions.
1.B is to the east of A.
2. B is to the west of A.
3. B is to the north of A.
4. B is to the south of A.
5. B is to the North East of A.
6. B is to the North West of A.
7. B is to the South East of A.
8. B is to the South West of A.
Direction: Ashok started walking towards South. After walking 50 meters he took a right turn and walked 30 meters. He then took a right turn and walked 100 meters. He then took a left turn and walked 30 meters and stopped. How far and in which direction was he from the starting point?
Solution:
Ashok started walking towards south.
After walking 50 meters...
..he took a right turn…
Some people have doubt in deciding left or right in direction questions; they can replace right by clockwise and left by anticlockwise. So now moving right (clockwise) from the tip of the arrow.
…and walked 30 meters.
He took a right turn…
…and walked 100 meters.
He took a left turn…
Now for finding how far he has moved, we will check two things:
Horizontal displacement = 30+30 = 60m
Vertical displacement = 100-50 = 50m
Final displacement = √(602+502) = √(3600+2500) = √6100 = 10√61 m
Now for finding the direction with reference to initial position, we will draw a line joining two points which will give us the direction.
We can clearly see that the direction in which Ashok moved is northwest.
So the final answer for this question will be “Ashok moved 10√61 meters in northwest direction”.
Directions: Jay starts his van from point X and covers a distance of 10 km towards west, then he turns north and covers a distance of 7 km. Again, he takes a right turn and covers 25 km. Now he covers 6 km, after taking a left turn. At last he takes a left turn and covers 15 km and stops at point Z.
Jay starts his van from point X and covers a distance of 10 km towards west
then he turns north
and covers a distance of 7 km
Again, he takes a right turn
…and covers 25 km
Now he covers 6 km, after taking a left turn.
At last he takes a left turn…
…and covers 15 km and stops at point Z.
Q. Towards which direction was the van running before stopping at point Z?
Solution: We can clearly see that van was running towards west before stopping at point Z.
So the correct answer is C.
Q. How far is Jay from point X?
Soution:
Horizontal movement = 10-25+15 = 0 kms
Vertical movement = 7+6 = 13 km
So final movement = = √(02+132) = √169 = 13 km
Direction of movement is North.
Question - Point B is 40√2m to the East of point A. Point C is 50m in the direction, which is 225 degree anticlockwise north of point B. Point D is 30m to the North-East of point C. Rahul started from point A, after crossing point B reaches to point E in east of point A. He took a right turn and after walking some distance he reaches to point D. find the total distance travelled by him?
Solution - Let us first draw some lines and take points, F and G such that Line CF is perpendicular to BE and also line DG is extension of line CD, which meets at G when BE line is extended in east direction of point E.
The required length is AB + BE + ED, we know length of AB that is 40m. We are required to find BE and ED. For BE and ED:- In triangle BCG, Angle C is 90 degree, angle B and G are of 45 degrees, and total length of line CG must be 50m (symmetry). BG ² = BC2 + CG2 (PT theorem) BG2 = 502 + 502 = 2*502 BG = 50 √2 Length of DG = CG – CD = 50 – 30 = 20m. In triangle DEG DE/DG = Sin45 DE/20 = 1/ √2, DE = 20/ √2 = 10√2 EG/DG = Cos45 EG/20 = 1/√2, EG = 20/√2 = 10√2 The length BE = BG – EG = 50√2 - 10√2 = 40√2 Total Distance covered by him = AB + BE + ED = 40 √2 + 40 √2 + 10 √2 = 90 √2
The sun rises in East direction. At the time of the sunrise/ morning, if a man is standing, the shadow of a man always falls on West.
The sun rises in West direction. At the time of the sunset/ evening, if a man is standing, the shadow of a man always falls on East.
There is no shadow at this time. At this time, the sun is exactly above our head, so no shadow is formed at 12'o clock.
Question: One morning, Sonu and Akhil were standing facing each other. Sonu’s shadow fell towards his right. Which direction was Akhil facing?
Solution - In the morning the sun is in the East so the shadow will form in the West. Thus, Sonu’s right is west i.e Sonu is facing south. Hence, Akhil is facing north.
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