The sides of a parallelogram are then the unit vector parallel to one of the diagonals is ........

The sides of a parallelogram are $(2\vec{i}+4\vec{j}-5\vec{k})$ , $(\vec{i}+2\vec{j}+3\vec{k})$ then the unit vector parallel to one of the diagonals is

$\frac{1}{7}(3\vec{i}+6\vec{j}-2\vec{k})$

$\frac{1}{7}(3\vec{i}-6\vec{j}-2\vec{k})$

$\frac{1}{7}(-3\vec{i}+6\vec{j}-2\vec{k})$

$\frac{1}{7}(3\vec{i}+6\vec{j}+2\vec{k})$

Explanation:

Diagonal will be D=A+B .Then divide by it's magnitude.

$\frac{1}{7}(3\vec{i}+6\vec{j}-2\vec{k})$

By: Swaminath Yadav

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The sides of a parallelogram are then the unit vector parallel to one of the diagonals is ........

Explanation:

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