Tangents drawn from the point P 1 8 to the circle touch the circle at the points A and B T...........

Tangents drawn from the point P (1, 8) to the circle $x^{2}+y^{2}-6x-4y-11=0$ touch the circle at the points A and B. The equation of the circum circle of the triangle PAB is

$x^{2}+y^{2}+4x-6y +19=0$

$x^{2}+y^{2}-4x-10y +19=0$

$x^{2}+y^{2}+2x+6y-29=0$

$x^{2}+y^{2}-6x-4y +19=0$

Explanation:

$x^{2}+y^{2}-4x-10y +19=0$

By: Swaminath Yadav

Profile ResourcesReport error

Submit Error

Let's Discuss

Post Comment

Explore
Micro
Courses

Free
Video
Courses

Free
Test
Series

Free
PDF
Documents

Back to Main Page

Tangents drawn from the point P 1 8 to the circle touch the circle at the points A and B T...........

Explanation:

Let's Discuss

Search below